Question

In the reaction between iodine and Na2S2O3 wch one is the oxidant and reductant

Answer 1

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HERE IS YOUR ANSWER!!!

WHEN IODINE IS REACT WITH NA2S2O3 THEN A COMPOUND IS FORM AFTER RELEASING S2

AS IT IS CONSIDERED AS DISPLACEMENT REACTION
WHERE IODINE DISPLACE SULPHUR

so in compound NA2S2O3 O.S OF SULPHUR IS+2 while in S2 STATE IT'S O.S IS O
HENCE ACT AS OXIDIZING AGENT (SHOW REDUCTION)



WHILE AS I2 HAS O O.S AND AFTER REACTION IT WILL FORM COMPOUND WITH +2O.S

HENCE ACT AS REDUCING AGENT (SHOW OXIDATION)


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