Question

IN THE REACTION CO+1/2O2----->CO2, N2+O2---->2NO. 10MLOFIXTURE CONTAINING CARBON MONOXIDE AND NITROGEN REQUIRED 7ML OXYGEN TO FORM CO2 AND NO, ON COMBUSTION. FIND THE VOLUME OF N2 IN THE MIXTURE

Answer 1

The reactions are as follows:

CO + 1/2O2 → CO2,

N2 + O2→ 2NO.

Or

1/2N2 + 1/2O2→ NO ------(1)

 

Now, out of 7 ml of oxygen, half of the oxygen will be used by CO to produce one mole of CO2 and half will be used by N2 to form one mole of NO.Therefore, volume of O2 used by N2 is 7/2 ml.

According to the equation  (1),

½ mole of N2 reacts with ½ mole of O2 to give one mole of NO.Therefore, same volume of N2 and O2 react to form NO.

Hence, the volume of N2 is 7/2 ml.

Answer 2

Answer:

4 ml

Explanation:

Let x be the volume of CO

Let 10-x be the volume of N₂

∴Volume of O₂ reacting with CO is x/2 (Since, for 1mole only 1/2 moles of O2 gets reacted.)                                                                               ----->(1)

Volume of O₂ reacting with N₂ is 10-x                                              ----->(2)

We know that the total volume of O₂ reacted is 7ml.                    

∴ x/2 + 10-2 = 7 (From 1 and 2)

=> x= 6ml

Therefore volume of Nitrogen is 4ml.

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