In the reaction equilibrium
A + B C +D,
(ii) what will happen if concentration of A is increased?
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Answer:
A+B⇌C+D
In this reaction equilitrian,
K
c
=
[A][B]
[C][D]
If we increase the concentration of C, the numerator (top) of the K
C
expression gets bigger. That would change the value of K
C
. In order for that not to happen until a new balance is reached, the concentration of C and D have to decrease again, and those of A and B increase. That happens until a new balance is reached when the value of K
C
reverts to what it was before. The position of equilibrium moves - not because of Le-chatelier's principle says it must - but because of the need to keep the constant value of equilibrium constant (K
C
).
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