In the reaction, H2 + I2 = 2HI, in a 2 litre flask 0.4 mole of each H2 and I2 are taken. At equilibrium 0.5 moles of HI are formed. What will be the value of equilibrium??????
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Answer:
0.09
Explanation:
H2 + I2 ◄─────► 2HI
mole at start 0.4 0.4 0
mole at equli. 0.4-α 0.4-α 2α
here , 2α=0.5 , α = 0.25
[H2] = (0.4-.25) /2
[I2] = (0.4-.25) /2
[HI]= 0.5/2
equilibrium cons. = ([H2][I2])/[HI]²
= 0.09
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