Question

In the reaction Lead Nitrate + Potassium Iodide → lead Iodide + potassium Nitrate

a) Lead iodide is the white insoluble substance formed.

b) Potassium nitrate is the yellow precipitate formed.

c) lead iodide is the yellow precipitate formed.

d) None of the above.

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Answer 1

Answer:

Case-1 : For 1st body of mass , m₁

Force , F = 5 N

Mass , m₁ = m₁ Kg

Acceleration , a = 10 m/s²

⇒ F = ma

⇒ 5 = m₁ (10)

⇒ m₁ = ¹/₂

⇒ m₁ = 0.5 Kg

Case-2 : For 2nd body of mass , m₂

Force , F = 5 N [ ∵ Same force ]

Mass , m₂ = m₂ Kg

Acceleration , a = 20 m/s²

⇒ F = ma

⇒ 5 = m₂ (20)

⇒ m₂ = ⁵/₂₀

⇒ m₂ = ¹/₄

⇒ m₂ = 0.25 Kg

Case-3 : For both bodies when tied together

Force , F = 5 N

Masses when tied together ,

⇒ m₁ + m₂ = 0.5 + 0.25

⇒ m₁ + m₂ = 0.75 Kg

Acceleration , a = ? m/s²

Apply Formula ,

⇒ F = ma

⇒ F = ( m₁ + m₂ ) a

⇒ 5 = ( 0.75 ) a

⇒ a = ⁵/₀.₇₅

⇒ a = 6.67 m/s²

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