Question

In the reaction mixture 2H2 + O2 2 H2O, H2 is 2.5g and O2 = 32g , the limiting reactant will be

PLEASE ANSWER THIS QUESTION , WILL MARK YOU THE BRAINLIEST ANSWER​

Answer 1

Hydrogen is a limiting reagent.

Given:

The mass of O₂ and H₂ is 2.5 g and 32 g respectively. O₂ + 2H₂ → 2H₂O

To Find:

The limiting reagent.

Solution:

To find the limiting reagent we will follow the following steps:

As we know,

The molecular mass of oxygen and hydrogen is 32g and 2 g respectively.

The limiting reagent is calculated by the ratio of moles and stoichiometry.

$Limiting \: reagent = \frac{moles}{stoichiometry}$

Now,

Moles of oxygen =

$\frac{32}{32} = 1$

Moles of hydrogen =

$\frac{2.5}{2} = 1.25$

Now,

Limiting reagent:

For Oxygen =

$\frac{1}{1} = 1$

For hydrogen =

$\frac{1.25}{2} = 0.625$

As the mole by stoichiometry for hydrogen is less than oxygen so, hydrogen is the limiting reagent.

Henceforth, hydrogen is a limiting reagent.

#SPJ3