Question

In the reaction

MnO, 4HCI MnCl,+ 2H,O+CL,
(a) Name the compound (i) oxidised, (ii) reduced.
(b) Define oxidation and reduction on its basis.

Answer 1

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$\mathfrak{\orange{\huge{Here\: is \:u\: r \:Ans}}}$⤵️⤵️⤵️

$\mathcal{\green{\huge{\star\: MnO2 + 4HCL 7 \: \star}}}$

------------->

MnCl2 7+ 2H2O + Cl2

▪ Here MnO2 is reduced to MnCl2

ie., The Oxidation no. Mn is descreased from +4 to -2 .

▪ HCL is oxidised to chlorine molecule.

▪ ie., The Oxidation no. of chlorine is increased from -2 to 0 .

▪ So, MnO2 is reduced to MnCl2 .

▪ HCL is Oxidised to Chlorine .

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