Question

in the reaction N2 + O2 gives and O2 at equilibrium concentration of N2 O2 Anu Anu 0.25 0.05 11 and respectively calculate initial concentration of N2 and O2

Answer 1

Answer: The initial concentration of $N_2\text{ and }O_2$ are 0.75 M and 0.55 M respectively.

Explanation:

We are given:

Equilibrium concentration of NO = 1 M

Equilibrium concentration of $N_2$ = 0.25 M

Equilibrium concentration of $O_2$ = 0.05 M

For the given chemical equation:

                   $N_2+O_2\rightarrow 2NO$

Initial:            a     b        -

At eqllm:     a-c    b-c     2c

Calculating the value of 'c'

$2c=1\\\\c=0.5$

Calculating the value of 'a' and 'b', we get:

For 'a'

$a-c=0.25\\\\a-0.5=0.25\\\\a=0.75M$

For 'b'

$b-c=0.05\\\\b-0.5=0.05\\\\b=0.55M$

Hence, the initial concentration of $N_2\text{ and }O_2$ are 0.75 M and 0.55 M respectively.