Question

In the reaction of chlorine with excess ammonia how many millimoles of ammonia are required to react with
0.213 gm of chlorine in giving products as per stoichiometric equation?​

Answer 1

Explanation:

Pure chlorine gas may react vigorously with ammonia gas. An excessive mix of the two gases in air can produce hazardous compounds such as nitrogen trichloride.

The following reaction takes place:

NH

3

+3Cl

2

⟶NCl

3

+3HCl

Ammonia reacts with excess of chlorine to form NCl

3

and HCl.

Answer 2

Given info : In the reaction of chlorine with excess ammonia.

To find : how many millimoles of ammonia are required to react with 0.213 gm of chlorine in giving products as per stoichiometric equation?

solution : stoichiometric reaction means, all of reactants are consumed and formed products.

here reactant, chlorine of mass 0.213 g has given.

reaction between chlorine and ammonia is ..

3Cl₂ + 8NH₃ ⇒6NH₄Cl + N₂

here you see, 3 moles of chlorine reacts with 8 moles of ammonia.

so, 3 × 71g of chlorine reacts with 8 moles of ammonia.

so, 0.213 g of chlorine reacts with 8/(7 × 71) × 0.213 = 0.008 mole ammonia

Therefore the no of moles of ammonia needed to consume all 0.213 g of Chlorine is 0.008 mole.