Question

In the reaction of k2 cr2 o7 + x h2 s o4 + y s o 2 equal to k 2 s o4 + cr2(so4)3 + z h2o the quotient x y and z respectively are

Answer 1

K2Cr2VIO7 + 3 SIVO2 +H2SVIO4 →Cr2III(SVIO4)3 + K2SVIO4+ H2O

This is an oxidation-reduction(redox) reaction:

3 SIV - 6 e- → 3 SVI(oxidation)

2 CrVI + 6 e- → 2 CrIII(reduction)