in the reaction, pcl5 ⇄pcl3+cl2,one mol each of pcl5 and pcl3 are initially present and at equilibrium X mol of pcl5 remain, what will be the total number of moles in the reaction at equilibrium
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Since x moles of PCl5 remains at equillibrium,1-x moles of PCl3 and Cl2 will be formed.so total no. of moles@ equillibrium is x+1-x+1-x=2-x
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