In the reaction represented by the following equation:
CuO (s) + H2 (g)
> Cu (s) + H2O (1)
(a) name the substance oxidised
(b) name the substance reduced
(C) name the oxidising agent
(d) name the reducing agent
Answers
Answered by
1
Answer:
H2 is oxidized,cu is reduced,hydrogen is oxidized,and copper is reduced
Answered by
0
Answer:
(a) The substance getting oxidized is Hydrogen-Water.
(b) The substance getting reduced is Copper Oxide-Copper.
(c) The oxidizing agent agent is Copper.
(d) The reducing agent is hydrogen.
please mark me the brainliest . That will do me good
Similar questions