In the reaction ![Cr_2O_7^{2-} + 14H^+ + 6I^- \longrightarrow 2Cr^{3+} + 7H_2O + 3I_2 Cr_2O_7^{2-} + 14H^+ + 6I^- \longrightarrow 2Cr^{3+} + 7H_2O + 3I_2](https://tex.z-dn.net/?f=Cr_2O_7%5E%7B2-%7D+%2B+14H%5E%2B+%2B+6I%5E-+%5Clongrightarrow+2Cr%5E%7B3%2B%7D+%2B+7H_2O+%2B+3I_2)
Which element is reduced
(a) I
(b) O
(c) H
(d) Cr
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Sis ANSWER TO THE QUESTION IS :-
OXYGEN ..
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