Question

In the reaction $H - C \equiv CH \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3} X \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3}$ X and Y are
(a) X = 1-Butyne ; Y = 3-Hexyne
(b) X = 2-Butyne ; Y = 3-Hexyne
(c) X = 2-Butyne ; Y = 2-Hexyne
(d) X = 1-Butyne ; Y = 2-Hexyne

Answer 1

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$\mathbb{NICE...QUESTION}$

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In the reaction $H - C \equiv CH \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3} X \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3}$ X and Y are
(a) X = 1-Butyne ; Y = 3-Hexyne
(b) X = 2-Butyne ; Y = 3-Hexyne
(c) X = 2-Butyne ; Y = 2-Hexyne
(d) X = 1-Butyne ; Y = 2-Hexyne


→ [B]


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Answer 2

Answer :

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In the reaction H - C \equiv CH \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3} X \xrightarrow[(2)CH_3CH_2Br]{(1)NaNH_2/ liq.NH_3} X and Y are  

(a) X = 1-Butyne ; Y = 3-Hexyne

(b) X = 2-Butyne ; Y = 3-Hexyne

(c) X = 2-Butyne ; Y = 2-Hexyne

(d) X = 1-Butyne ; Y = 2-Hexyne

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The correct option is (b) :  (b) X = 2-Butyne ; Y = 3-Hexyne

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