Question

In the reaction VO+Fe2O3--->FeO+V2O5, the eq. wt. of V2O5 is equal to its M V2O5=182a.45.6b. 53.2c. 30.33d. 63.2​

Answer 1

Answer:

(c) 30.33

Explanation:

$VO + Fe_{2} O_{3} -----> FeO + V_{2} O_{5}$

VO ---->$V_{2} O_{5}$

Multiplying LHS by 2 to balance the equation,

2VO ----> $V_{2} O_{5}$

Oxidation No. of V in VO = +2 and in 2VO = 2 x 2 = +4

Oxidation No. of V in $V_{2} O_{5}$ = +5 x 2 = + 10

Change in oxidation number or n- factor = 10 - 4 = +6

Equivalent Weight = Molecular weight/n- factor

Equivalent weight = 182/6 = 30.33 amu

Hope it helps..!! ^_^