Question

In the reactions how to represent y in terms of x
HCl +NaOH = NaCl + H2O + x cal. H2SO4 + 2NaOH = Na2SO4 + 2H2O+ y cal

Answer 1

HCl + NaOH  NaCl + H2O

So number of moles of water formed = 0.1

Number of moles of acid used = Number of moles of alkali

= C x V (in litres) = 1 x 0.1 = 0.1

Use proportion to find the amount of heat given out when 1 mole

of water is formed.

0.1 mole  -5.18 kJ

So 1 mole  1/0.1 x –5.18 = -51.8 kJ mol-1

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