Question

in the rectangle ABCD, angle BAC=4x and angle BCA =5x.find measures of angle ACB and angle CAD.

Answer 1

ABC + BAC + BCA = 180°
90° + 4x + 5x = 180°
9x = 180° - 90°
x = 90° ÷ 9
x = 10°

BAC = 4×10
= 40°

BCA = 5×10
=50°

ACB = 50°
because BCA =50°

BAD = BAC + CAD
90° = 40° + CAD
therefore CAD = 90° - 40°
therefore CAD = 50°