in the rectangle ABCD diagonals AC and BD intersect at O if angle BOC=68° find the value of x
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The answer is
Angle AOD = Angle BOC
( Vertically Opposite Angles )
Angle AOD = 68°
Angle ADO + Angle DAO + Angle AOD = 180°
( Angle Sum Property )
Angle ADO + Angle DAO + 68° = 180°
2 Angle ADO = 180° - 68°
( Angle ADO = Angle DAO )
2 Angle ADO = 112°
Angle ADO = 56°
Angle DAB = Angle DAO + x
90° = 56° + x
x = 34°
Hope it helps you .
Have a nice day .
Angle AOD = Angle BOC
( Vertically Opposite Angles )
Angle AOD = 68°
Angle ADO + Angle DAO + Angle AOD = 180°
( Angle Sum Property )
Angle ADO + Angle DAO + 68° = 180°
2 Angle ADO = 180° - 68°
( Angle ADO = Angle DAO )
2 Angle ADO = 112°
Angle ADO = 56°
Angle DAB = Angle DAO + x
90° = 56° + x
x = 34°
Hope it helps you .
Have a nice day .
Mehak885:
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