in the rectangle ABCD, prove that ACB=DBC
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In a rectangle opposite sides are parallel
In a rectangle opposite sides are parallel So AC∣∣BD
In a rectangle opposite sides are parallel So AC∣∣BDHere CB acts as tranversal
In a rectangle opposite sides are parallel So AC∣∣BDHere CB acts as tranversal So by Alternate interior opposite angles
In a rectangle opposite sides are parallel So AC∣∣BDHere CB acts as tranversal So by Alternate interior opposite angles ∠ACB=∠CBD
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