in the rectangle ABCD2,AB=(3x+y)cm,BC=(3x+2)cm,CD=(3y-2x)cm and DA=(y+3)cm. what is the pair of simulataneous equations required to determine the length of each the sides of rectangle ABCD
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Given: The equation of sides AB=(3x+y)cm, BC=(3x+2)cm, CD=(3y-2x)cm and DA=(y+3)cm.
To find: what is the pair of simulataneous equations required to determine the length of each the sides of rectangle ABCD
Solution:
- Now we have given the equation of the sides of the rectangle as:
AB=(3x+y)cm, BC=(3x+2)cm, CD=(3y-2x)cm and DA=(y+3)cm.
- Now the simulataneous equations required to determine the length of each the sides of rectangle ABCD is:
AB=DC
3x + y = 3y - 2x
3x + 2x = 3y - y
5x = 2y
x = 2y/5
BC=DA
3x + 2 = y + 3
- Putting value of x in this, we get:
3(2y/5) + 2 = y + 3
6y/5 + 2 = y + 3
6y/5 - y = 1
6y-5y = 5
y = 5
x = 2
Answer:
So the value of x is 2 and y is 5.
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