Question

In the rectangular box shown, find
a) AC
b)AR
c)The angle between AC & AR​

Answer 1

Step-by-step explanation:

We know, diagonal of a rectangle= √(l²+b²)

so,

AC=

$\sqrt{ ({12}^{2} + {5}^{2} )}$

$= \sqrt{144 + 25}$

$= \sqrt{169}$

$= 13$

AR=

$\sqrt{ {12}^{2} + {5}^{2} + {4}^{2} }$

$= \sqrt{144 + 25 + 16}$

$= \sqrt{185}$

Let the required angle be θ

$\cos( \theta) = \frac{13}{ \sqrt{185} }$

$= > \theta = \cos^{ - 1} ( \frac{13}{ \sqrt{185} } )$

Answer 2

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Step-by-step explanation:bcddf

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