In the rectangular parallelepiped shown, points are each at the midpoint of an edge. _____18. What is the area of section JKL?
a) 5.03 b) 5.81 c) 9.52 d) 11.68
_____19. What is the area of section BDP?
a) 5.03 b) 5.81 c) 9.52 d) 11.68
_____20. What is the area of section JKMN?
a) 5.03 b) 5.81 c) 9.52 d) 11.68
add solution pls
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Given : In the rectangular parallelepiped shown, points are each at the midpoint of an edge
To Find : What is the area of section JKL?
a) 5.03 b) 5.81 c) 9.52 d) 11.68
Solution:
AD = BC = GF = HE = 5
AB = CD = F = HG = 3
AG = DG = CE = BH = 4
AJ = AB/2 = 3/2
AL = AG/2 = 2
AK = AD/2 = 5/2
JL =√AJ² + AL² = √ (3/2)² + 2² = 5/2
JK = =√AJ² + AK² = √ (3/2)²+(5/2)² = √34/2
KL = =√AL² + AK² = √ 2²+(5/2)² = √41/2
Area of Δ JKL with sides 5/2 , √34/2 , √41/2 ≈ 3.47 sq uits
3.47 sq uits
None of the given option matches
Looks some mistake in data
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