Question

In the redox reaction
x Zn + y NO3 + H20 a Zn2+ + b NH + COH-
the value of coefficients x, y and c respectively in
balanced reaction are

Answer 1

x = 5, y = 2 and z = 7

reaction is .....

x Zn + y NO3^- + z H2O ⇔aZn²+ b NH4^+ + c OH-

here Zn is oxidised into Zn²+

so, Zn ⇔Zn²+ + 2e.........(1)

and NO3^- is reduced into NH4^+

so, NO3^- ⇔NH4^+

now balancing by adding 3 hydroxyl ions in right side.

i.e., NO3^- ⇔NH4^+ + 3OH^-

7 hydrogens present in right side which are balanced by adding 7 H^+ in left side.

i.e., 7H^+ + NO3^- ⇔NH4^+ + 3OH^-

now, 7H^+ + NO3^- + 5e ⇔NH4^+ + 3OH^- ..........(2)

5 × equation (1) + 2 × equation (2)

we get, 5Zn + 14H^+ + 2NO3^- ⇔5Zn²+ + 2NH4^+ + 6OH^-

adding 7OH^- both sides to get 7H2O in left side.

or, 5Zn + 7H2O + 2NO3^- ⇔5Zn²+ +2NH4^+ + 13OH^- this is completely balanced chemical equation.

now compare it we will get

x = 5, y = 2 and z = 7

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Answer 2

Answer: X=4 y=1 c= 10

Explanation: make the balancing equation for atoms other than H&O.

Zn→Zn^+2 + 2e-. (1)

Now,

N03^-1 + 8e- → NH4^+1

Now we balance the oxygen

7H+ +NO3^-1 + 8e- → NH4^+ + 3OH-. (2)

Adding both equation after multiplying 8 to (1) and 2 to (2).

We get

8Zn + 14H+ +2NO3^-1 → 8Zn^+2 + 2NH4^+ 6OH-

Simplify it and add OH- on both sides to balance so the final balanced equation is..

4Zn + NO3^-1 + 7H20 → 4Zn^+2 + NH4^+ + 10 OH- ..