In the reduction of nitric oxide, 50% of reaction was completed in 108 seconds when initial pressure was 336 mm Hg and in 147 seconds initial pressure was 288 mm Hg. Find the order of the reaction.
Answers
In the reduction of nitric oxide, 50% of reaction was completed in 108 seconds when initial pressure was 336 mm Hg and in 147 seconds initial pressure was 288 mm Hg. Find the order of the reaction.
The order of the reaction is 3.
Given: 50% of the reaction was completed in 108 seconds when initial pressure was 336 mm Hg and in 147 seconds initial pressure was 288 mm Hg.
To Find: The order of the reaction.
Solution:
The question can be solved using the formula for half reaction,
t ∝ ( P )^(1-n) [ where t = time taken, P = pressure achieved, n = order ]
According to the given information,
t1 = 108 s , t2 = 147 s, P1 = 336 mm Hg , P2 = 288 mm Hg.
Thus,
( t1 / t2 ) = ( P1 / P2 )^(1-n)
⇒ ( 108 / 147 ) = ( 336 / 288 )^(1-n)
⇒ ( 36 / 49 ) = ( 7 / 6 )^(1-n)
⇒ ( 7 / 6 )^-2 = ( 7 / 6 )^(1-n)
Now, since bases are the same, so we can directly compare the powers,
∴ 1 - n = -2
⇒ n = 3
Hence, the order of the reaction is 3.
#SPJ3