In the regular hexagon
ABCDE, EB and CF are
the angle bisectors of
E and C, respectively.
Find BOC.
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Answer:
∠BOC=60°
Step-by-step explanation:
in the Δ BOC
∠B=∠C=120°
OB and OC are bisectors of ∠B and ∠C
so ∠OBC=∠OCB=60°
Thus in the ΔOBC
∠OBC+∠OCB +∠BOC=180°
60+60+∠BOC=180
∠BOC=180-120=60
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