Question

In the relation F = a sin Bx + c sin d t where F is Force, x is displacement and t is time then what is the dimension of D /B​

Answer 1

Answer:

F=A cos Bx+C sin Dt

It is a common saying in mathematics that the elements inside cos and sin function is always constant.

So here in the above equation

B x. & Dt must be dimensionless

Since x=[L] &t=[T]

So B=[L]^-1 & D=[T]^-1

So,D/B=[LT^-1]