Physics, asked by AditiLohiya, 15 days ago

In the relation P=alpha/beta e^-alpha z/k theta ;P is pressure,k is Boltzman constant,Z is distance and theta is temperature .The dimensional formula of beta will be _____????​

Answers

Answered by kiranchoudhary1107
0

Since exponential term is dimensionless,

Dimension of α, [α]=

[Z]

[k][θ]

=

L

(ML

2

T

−2

K

−1

)∗(K)

=MLT

−2

Since

β

α

must have the dimensions of pressure(ML

−1

T

−2

)

Therefore, dimensions of β, [β]=

ML

−1

T

−2

MLT

−2

=L

2

Good morning

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