In the relation P=alpha/beta e^-alpha z/k theta ;P is pressure,k is Boltzman constant,Z is distance and theta is temperature .The dimensional formula of beta will be _____????
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Since exponential term is dimensionless,
Dimension of α, [α]=
[Z]
[k][θ]
=
L
(ML
2
T
−2
K
−1
)∗(K)
=MLT
−2
Since
β
α
must have the dimensions of pressure(ML
−1
T
−2
)
Therefore, dimensions of β, [β]=
ML
−1
T
−2
MLT
−2
=L
2
Good morning
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