Question

In the Rhombus ABCD ABC is equals to 40 then ADB is

Answer 1

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$\bold{Explanation:}$

hi friend

here's your answer looking for

in rhombus ABCD,

angle ACB = angle CAD = 40. (. alt int. angle )

now,

angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)

so, in triangle AOD ,

angle COD + angle AOD +angle ODA = 180

40 + 90 + ADB = 180

ADB = 180 - 130= 50

so, this is your answer

hope you are satisfied with my answer

Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

in rhombus ABCD,

angle ACB = angle CAD = 40. (. alt int. angle )

now,

angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)

so, in triangle AOD ,

angle COD + angle AOD +angle ODA = 180

40 + 90 + ADB = 180

ADB = 180 - 130= 50

HOPE SO IT WILL HELP.....

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