In the right angle ΔABC, ∠B=900. If tan C = 3 , the value of the angle ‘A’ is
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Step-by-step explanation:
\begin{gathered} \bold {\: sum \: of \: all \: sides \: of \: triangle \: = 180 \degree} \\ \tan(60\degree) = \sqrt{3} \\ \angle \huge \: c \: = 60 \degree \\ \huge \angle \: \: a \: + \angle \: b \: + \angle \: c \: = 180 \degree \\ \huge \angle \: a \: + 90 \degree \: + 60 \degree \: = 180 \degree \\ \huge \angle \: a + 150 \degree \: = 180 \degree \\ \huge \angle \: a \: = 180 \degree \: - 150 \degree \\ \huge \angle \: a \: = 30 \degree\end{gathered}
sumofallsidesoftriangle=180°
tan(60°)=
3
∠c=60°
∠a+∠b+∠c=180°
∠a+90°+60°=180°
∠a+150°=180°
∠a=180°−150°
∠a=30°
Step-by-step explanation:
the is answer
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