Question

In the right angle triangle PQR, angle P=90°. If l (PQ)=24cm and l(PR)=10cm, find the length of seg QR?

Answer 1

According to Pythagorus theorem
H^2=p^2+b^2
QR^2=PQ^2+PR^2
QR^2=24^2+10^2
QR^2=576+100
QR^2=676
QR=_/676
QR= 26cm
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Answer 2

Answer:

Solution:

Maharashtra Board Class 7 Maths Solutions Chapter 13 Pythagoras' Theorem Practice Set 48 2

In ∆PQR, ∠P = 90°.

Hence, side QR is the hypotenuse.

According to Pythagoras’ theorem,

l(QR)² = l(PR)² + l(PQ)²

∴ l(QR)² = 10² + 24²

∴ l(QR)² = 100 + 576

∴ l(QR)² =676

∴ l(QR)² = 26²

∴ l(QR) = 26 cm

∴ The length of seg QR is 26 cm.