Question

in the right -angled ∆ PQR , <p=90°. if (PQR) =24 cm and (PR)=10 cm find the length of segQR​

Answer 1

Let QR be the hypotenuse of ∆PQR,

<p=90°

by Pythagoras Theorem,

(RQ)^2 = (PR)^2 + (PQ)^2

RQ^2=10^2+24^2

RQ^2=100+576

RQ^2=676

RQ=√676

QR=26cm.