Question

In the right angled ΔPQR, PQ = QR, If PQ = √32 , find PR​

Answer 1

Step-by-step explanation:

hyp

${hypotenuse}^{2} = {side}^{2} + {side}^{2} \\ {pr}^{2} = {pq}^{2} + {qr}^{2}$

$\sqrt{32 {}^{2} } = \sqrt{32 {}^{2} } + {qr}^{2}$

solve for answer