In the right angled triangle abc angle c = 90 degree angle b = 60 degreev. if ac =6cm find the lengths of the side bc and ab
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In this triangle ab is hypotenuse,ac is perpendicular and bc is base of the triangle.
Given is.... angle b =60°
angle c=90°
ac= 6 cm.
Now , tan b= ac/bc
tan 60° = 6/bc
√3 = 6/ bc
So, bc = 2√3
Now, ab^2= ac^2+bc^2
ab^2= 6*6 + 2√3*2√3
ab^2= 36+12
ab= √48
ab=4√3
I hope this would help.
Given is.... angle b =60°
angle c=90°
ac= 6 cm.
Now , tan b= ac/bc
tan 60° = 6/bc
√3 = 6/ bc
So, bc = 2√3
Now, ab^2= ac^2+bc^2
ab^2= 6*6 + 2√3*2√3
ab^2= 36+12
ab= √48
ab=4√3
I hope this would help.
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