In the right-angled triangle ABC, angleC = 90° and angle b= 60°. If AC = 6 cm, find th
lengths of the sides BC and AB.
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Answer:
AB=4√3
BC=2√3
Step-by-step explanation:
given:
c=90
b=60
cos 60=BC/AB
⇒1/2=BC/AB
sin 60=AC/AB
⇒√3/2=6/AB
AB=4√3
BC=2√3
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