Question

In The Right angled triangle ABC is common the CBA = ?


LoL ✓​

Answer 1

Answer:

In △ABD and △ABC we have BD=BC

AB=AB [Common]

∠ABD=∠ABC=90

∘

∴ By SAS criterion of congruence we get

△ABD≅△ABC

⇒AD=AC and ∠DAB=∠CAB [By CPCT]

⇒AD=AC and ∠DAB=x [∴∠CAB=x]

Now, ∠DAC=∠DAB+∠CAB=x+x=2x

∴∠DAC=∠ACD

⇒DC=AD [Side Opposite to equal angles]

⇒2BC=AD since DC=2BC

⇒2BC=AC Since AD=AC

Hence proved

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Answer 2

Answer:

In △ABD and △ABC we have  BD=BC

AB=AB [Common]    

∠ABD=∠ABC=90  

∘

 

∴ By SAS criterion of congruence we get    

△ABD≅△ABC  

⇒AD=AC and ∠DAB=∠CAB [By CPCT]  

⇒AD=AC and ∠DAB=x [∴∠CAB=x]    

Now, ∠DAC=∠DAB+∠CAB=x+x=2x

∴∠DAC=∠ACD

⇒DC=AD [Side Opposite to equal angles]

⇒2BC=AD since DC=2BC

⇒2BC=AC Since AD=AC

this is aaysha ? pehechana

Explanation: