In the right angled triangle if ∠ = ∠ A C find
the value of ∠ACD .
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ACD=90°+x
but in triangle ABC ,A+B+C=180°
if B=90° then,x+y=90°
hence ACD=2x+y
but in triangle ABC ,A+B+C=180°
if B=90° then,x+y=90°
hence ACD=2x+y
Answered by
1
∠BAC=∠ACB
∠BAC+∠ACB+∠CBA=180°
∠ACB+∠ACB+90=180
2∠ACB=180-90
∠ACB=90/2
∠ACB=45
- ∠ACB+∠ACD=180
∠45+∠ACD=180
∠ACD=180-45
- ∠ACD=135
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