In the right angled triangle MNO M MZM = 60°, mzo = 30° and 60 12 cm seg. MO = 12 cm. Find the length of seg NO. 30 N 0
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Given: Right angles Triangle MNO
m∠M = 60° , m∠O = 30° , Seg MO = 12 cm
To Find : Length of seg NO
Solution:
m∠M = 60° , m∠O = 30°
Hence ΔMNO is right angled at N
Sin ∠M = NO / MO
=> Sin 60° = NO / 12
=> NO = 12 Sin 60°
=> NO = 12 ( √3 / 2)
=> NO = 6√3
the length of seg NO 6√3 cm
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