Question

In the right-angled triangle QPR, PM is an altitude. Given that QR = 8cm and MQ = 3.5 cm,

Answer 1

We have

∠QPR = ∠PMR = 90°

∠PRQ = ∠PRM (common)

ΔPQR ~ ΔMPR (AA similarity)

then QR/PR=PR/MR

(PR)2=8×4.5=36

PR=6cm

Answer 2

hey mate here is ur answer

given that,

/_ QPR = /_ PMR = 90

/_ PRQ = /_ PRM = common

/\ PQR ~ /\ MPR

SO,,,

$\frac{QR}{PR} = \frac{PR}{MR} \\ \\{PR}^{2} = 8 \times 4.5 \\ \\ {PR}^{2} = 36 \\ \\ PR = 6$

hope this helps u PLZZ mark as BRAINLIEST