Question

in the right angled triangle, sides making right angle 8 and 11 cm find length of the hypotenuse?​

Answer 1

Answer:

√185 cm

Step-by-step explanation:

Given measurements of the sides = 8cm and 11cm .

Let the hypotenuse be h .

According to the Pythagoras theorem ,

(8)² + (11)² = (h)²

⟹ 64 + 121 = 185

⟹ √64 + √121 = √185

⟹ 8² + 11² = √185

Answer 2

Given:-

• Base of thr right angled triangle ➜8 cm
• Perpendicular of a triangle ➜ 11 cm

To find :-

• The hypotenuse of the right angled triangle.

Solution :-

➠ Base = 8cm

➠ Perpendicular = 11 cm

➠ Hypotenuse = ?

By using Pythagoras theorem

we get,

$\implies \sf{AB^2+BC^2=AC^2}$

$\implies\sf{AC^2=AB^2+BC^2}$

$\implies\sf{AC^2=(11)^2+(8)^2}$

$\implies\sf{AC^2=121+64}$

$\implies\sf{AC^2=185}$

$\implies\sf{AC= \sqrt{185} }$

Therefore,

Your answer is √185 .