Question

in the right angles ∆PQR angle Q = 90°,PQ = 8, QR = 15 and PR = 17 find the ratios of SIN P , SIN R , and TAN P​

Answer 1

Answer:

Given that cosA=

37

35

. Let us consider △ABC (see fig), ∠B=90

∘

, with AB=35 and AC=37d. By Pythagoras theorem, we have

AC

2

=AB

2

+BC

2

37

2

=35

2

+BC

2

BC

2

=37

2

−35

2

=1369−1225=144

∴BC=

144

=12

secA=

AB

AC

=

35

37

,tanA=

AB

BC

=

35

12

Now, secA+tanA=

35

37

+

35

12

=

35

49

,secA−tanA=

35

37

−

35

12

=

35

25

∴

secA−tanA

secA+tanA

=

35

25

35

49

=

35

49

×

25

35

=

25

49

solution

Step-by-step explanation:

I hope this will help you