Math, asked by rocky0424, 9 months ago

In the right triangle ABC <B =900 , AB = 6 cm, BC = 8 cm. the circumradius of this triangle is​

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

∠B = 90°

Thus area of the triangle A=1/2*AB*BC

A=1/2 *6*8=24 cm²

AC=√(AB²+BC²)=√(36+64)=10 cm

Thus Circumradius R =abc/4A

=BC*CA*AB/4A

=8*6*10/4*24

R=480/96=5 cm

Answered by Anonymous
13

Answer:

R = 5 cm

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