In the right triangle, B is a point on AC such that AB+ AD= BC+ CD . If AB=x, BC= h , and CD = d , then x will be
a) 2hd/ 2h+d
b) 2hd/h-d
c) hd/h+2d
d) hd/2h+d
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d)hd/2h+d I am right I am not sure
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