In the right triangle Sin (40-x)=cos(3x) what is the value of x
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Answered by
7
Right angle triangle is one which one of the angle must be 90 degree.
sin (40-x)= cos (3x)
According to trigonometry identity cosθ= sin (90-θ)
sin(40-x)= sin (90-3x)
(sin on both the sides gets cancelled)
Therefore:-
40-x= 90-3x
3x-x=90-40
Subtracting the like terms on RHS and LHS,
2x = 50
Taking 2 on right hand side,
x= 50/2
Therefore, the value of x is 25.
Answered by
0
sin( 40 - x) = cos3x
=>cos( 90 - (40 - x) ) = cos 3x
=>50 + x = 3x
=>2x = 50
=>x = 25
formula used
sin( 90 - a) = cosa
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