Question

in the rose garden there are 32 roses plants in the First row 29 in the second row 26 in the third row and so on there are 5 Rose plants in the last row how many rows of Rose plants are there in Rose garden​

Answer 1

Answer ==> 10

Solution : AP formed here is 32,29,26....5

therefore, a = 32

d = (-3)

let 5 be nth term.

therefore, a + ( n - 1 )(d) = 5

=> 32 + ( n - 1)(-3) = 5

=> (n - 1)(-3) = -27

=> n - 1 = 9

=> n = 10

therefore there are 10 rows of rose plants.

Answer 2

Answer:

10 rows

Step-by-step explanation:

a= 32 d= -3 tn= 5

By using,

tn=a+(n-1)d

Substitute the value of a, d, tn

5 = 32+(n-1)(-3)

5-32= -3n+3

-27= -3n+3

-27-3= -3n

-30= -3n

10 =n

n =10