In
The screen is 1.2m
away from
young's double slit experiment the slits are
separated by 0.24 num. The screen
the slits. The fringe width is 0.3 im Calculate the
wavelength of the light used in the experiment.
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Answered by
1
Answer:
Explanation:
=10
−3
m
D=1m
λ=500×10
−9
m
The width of central maxima in a single slit diffraction:
a
2λD
Fringe width in double slit pattern: β=
d
λD
Given,
10β=
a
2λD
⇒10
d
λD
=
a
2λD
⇒a=
5
d
mm=0.2mm
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