in the sequance a three digit numbers below 500 which leaves riminder 1 when divided by 7
Answers
Answered by
2
Answer:
498
Step-by-step explanation:
hope it's help you
you have to bring remainder 1 then 498 is the correct answer.
Answered by
1
Answer:
a
n
=l=498 ⇒
a_{n} =a_{1} +(n-1)da
n
=a
1
+(n−1)d ⇒
498=8+(n-1)7498=8+(n−1)7 ⇒
498=8+7n-7498=8+7n−7 ⇒
498-1=7n498−1=7n ⇒
71=n71=n
S_{n} =\frac{n}{2} (a+l)S
n
=
2
n
(a+l) ⇒
S_{71} =\frac{71}{2} (8+498)S
71
=
2
71
(8+498) ⇒
S_{71} =\frac{71}{2} (506)=17.963S
71
=
2
71
(506)=17.963
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