in the sequence 0.12,0.17,0.22, find n if the nth term is 67
Answers
Answer:
Given an arithmetic sequence 0.12,0.17,0.22,...0.12,0.17,0.22,... where the first term a1=0.12a
=0.12 . our goal is to find the 67th term a{67}
.
First thing to do is to find the common difference dd . Without solving, we can observe that the difference between 0.170.17 & 0.120.12 and 0.220.22 & 0.170.17 is 0.050.05 . We then say that d=0.05d=0.05 .
We can now plug in the values to the explicit formula an=a1(n-1)d
n=a1 +(n−1)d
a 67
Therefore, the 67th term of the sequence is 3.42
Given : sequence 0.12,0.17,0.22
nth term is 0.67
To Find : n
Solution:
Arithmetic sequence : Sequence of terms in which difference between one term and the next is a constant.
This is also called Arithmetic Progression AP
Arithmetic sequence can be represented in the form :
a, a + d , a + 2d , …………………………, a + (n-1)d
a = First term
d = common difference = aₙ-aₙ₋₁
nth term = aₙ = a + (n-1)d
Sₙ = (n/2)(2a + (n - 1)d)
sequence 0.12,0.17,0.22
d = 0.17 - 0.12 = 0.05
0.22 - 0.17 = 0.05
a = 0.17
d = 0.05
nth term =0.67
0.67 = 0.17 + (n - 1)0.05
=> 0.5 = (n - 1)(0.05)
=> n - 1 = 10
=> n = 10 + 1
=> n = 11
11th term is 0.67
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