Question

In the sequence 2,5,8.....upto 50 terms and 3,5,7....upto 60 terms ,find the no. of identical terms?​

Answer 1

Answer:

For the first A.P

An=2+(x−1)3=3x−1 when 0<x<51

For second A.P,

Bn=3+(y−1) 2 =2y+1 when 0<y<61

where x and y are inyegers.

when x is an even no., it satisfies this condition.

Hence

x=2, y=2

x=4, y=5

x=6, y=8

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x=40, y=59

Hence, 20 terms are identical.

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