Math, asked by karajrandhawa9304, 1 year ago

In the sequence 4 2 6 1 3 8 9 5 8 1 6 5 1 5 8 5 3 9 4 9 2 3 2 1 5 7 2 6 2 4 2 7 4 how many such 2s are there in the above arrangement each of which is immediately preceded by an odd digit and also immediately followed by an odd digit? Select one: a. None b. Three c. Two d. One

Answers

Answered by swethasurendramalya
0

Answer:

TWO

Step-by-step explanation:

Answered by combrinckdayle
0

Answer:

C. Two

Step-by-step explanation:

(0) 4 2 6 is not right as there are even numbers on either side of the two.

(1) 9 2 3 is the first one because there is odd numbers on either side of the two.

(2) 3 2 1 is the second one because there is odd numbers on either side of the two.

(0) 7 2 6 is not right because it only has one odd number next to it the other one is and even number.

(0) 6 2 4 is not right as there are even numbers on either side of the two.

(0) 4 2 7 is not right because it only has one odd number next to it the other one is and even number.

So there is only two of them.

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