In the sequence 4 2 6 1 3 8 9 5 8 1 6 5 1 5 8 5 3 9 4 9 2 3 2 1 5 7 2 6 2 4 2 7 4 how many such 2s are there in the above arrangement each of which is immediately preceded by an odd digit and also immediately followed by an odd digit? Select one: a. None b. Three c. Two d. One
Answers
Answered by
0
Answer:
TWO
Step-by-step explanation:
Answered by
0
Answer:
C. Two
Step-by-step explanation:
(0) 4 2 6 is not right as there are even numbers on either side of the two.
(1) 9 2 3 is the first one because there is odd numbers on either side of the two.
(2) 3 2 1 is the second one because there is odd numbers on either side of the two.
(0) 7 2 6 is not right because it only has one odd number next to it the other one is and even number.
(0) 6 2 4 is not right as there are even numbers on either side of the two.
(0) 4 2 7 is not right because it only has one odd number next to it the other one is and even number.
So there is only two of them.
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