Question

in the sequence 74,80,86.....find the 32th term​

Answer 1

Answer:

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Answer 2

Answer:

heya mate there's your answer

Given series 74,80,86,...................is in AP

let first term of the AP be a1 =74

second term of the AP be a2=80

and common difference of the AP be d

d=a2-a1

=80-74

=6

so common difference of the AP is d=6

we know that,

nth term of an AP is

an=a1+(n-1)d

32th term is,

a32=74+(32-1)(6)

=74+(31)(6)

=74+186

=260

So 32th term of the AP is 260.

hope it helps you

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